Bug 139375

Open a Java class having a constructor without access modifier e.g.

1: public class XYZ(){
2:  int a;
3:  public XYZ() {
4:  }
5: 
6: XYZ(int a){
7:  this.a = a;
8: }
9:}

Go to Tools->Options ->Fonts & Colors
Select Syntax tab and select Java as the Language.
Click on "Constructor declaration" and assign a unique color (lets say Purple)
Click on "Indentifier" and assign a unique color (lets say Orange)
Save settings and go back to the class.

Bug:-
We will see constructor at line number 4 (Constructor with access modifier) will be in Purple but the constructor at
line number 6 (Constructor without access modifier) will be in Orange. The moment we add an access modifier the
constructor (at line 6) the color changes to Purple.

A related issue is -
Go to Tools->Options ->Fonts & Colors
Select Syntax tab and select Java as the Language.
We see a sample code.
When we click on the 'method' in the sample code, it takes us to modify the color of 'Identifier'. It should take us to
modify the 'Method Declaration' color.
Similarly, When we click on the 'String' in the sample code, it takes us to modify the properties of 'Identifier'. It
should take us to modify the 'Class Use' color.
Similarly, When we click on the 'param' in the sample code, it takes us to modify the properties of 'Identifier'. It
should take us to modify the 'Parameter declaration' color.