In the code example below, at the very end, there is a switch statement.
It switches through C++11 enum class enumerators
Its body is generated by the IDE.
Class name is printed twice - Token::Token::Kind::NUMBER instead of Token::Kind::NUMBER
Although it compiles OK, the code looks weird.

class Token {
public:
  enum class Kind {
    NUMBER,
    ALL,
    LAST,
    DBL_PERIOD,
    LPAREN,
    RPAREN,
    COMMA,
    MINUS,
    INVALID,
    EOD // end of data marker
  };
private:
  Token::Kind kind;
  int value;
public:
  Token(Token::Kind k, int v = 0);
  int getValue();
  Kind getKind();
  bool isValid();
  Token& operator=(const Token& other);
  Token(const Token& other);
};

class Tokenizer {
  const char* curr;
  bool errors;
public:
  Tokenizer(const char* Curr);
  bool HasErrors();
  Token NextToken();
};

void Parse(const char* rule) {
  Tokenizer tokenizer(rule);
  Token tok(Token::Kind::INVALID);
  while ((tok = tokenizer.NextToken()).isValid()) {
    switch (tok.getKind()) {
      // this switch body is generated
      case Token::Token::Kind::NUMBER: // should be Token::Kind::NUMBER
        break;
      case Token::Token::Kind::ALL: // should be Token::Kind::ALL
        break;
    // ...    
      default:
        break;
    }
  }
}