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Hi, class C{ public: C(){} ~C(){} virtual void doit(){} }; template <class T> class B{ public: typedef int basic_type; B(){} ~B(){} virtual void doit(){} }; template <typename X> class A: public B<X>{ public: A(){} A(X* x):m_x(x){} ~A(){} void doit(){} void doit2(){ doit(); m_x->doit(); } X* getX(){return m_x;} protected: X* m_x; }; int main() { A<C> a; a.doit2(); <------------- calling "call graph" here return 0; } At "a.doit2()" the call graph only outputs: A::doit2 ---> A::doit , omitting the C::doit (given by m_x->doit(), with m_x type being C). Thanks, Rolando
Hi, I am not sure, but perhaps when we have the http://editor.netbeans.org/issues/show_bug.cgi?id=158692 implemented, we could have multiple "sub-graphs" per a function call. Example: class C{ public: C(){} ~C(){} virtual void doit(){} }; class D{ public: C(){} ~C(){} virtual void doit(){} }; class E{ public: C(){} ~C(){} virtual void doit(){} }; template <typename X> class A{ public: A(){} A(X* x):m_x(x){} ~A(){} void doit(){} void doit2(){ <---- Calling call graph here doit(); m_x->doit(); } X* getX(){return m_x;} protected: X* m_x; }; if we called "call graph" on A::doit2 we could obtain the following: A::doit2 | V A::doit | --------------------- | | | C::doit D::doit E::doit Thanks, Rolando