Pointer Arithmetic Problem

  • From: "ali_uk" < >
  • To:
  • Subject: Pointer Arithmetic Problem
  • Date: Fri, 01 Feb 2013 15:22:11 -0500

Hello All

I am learning about pointers in C.

Can someone please tell me why I get 67 instead of 22 when I run the code 
The code compiles and runs OK.  All the other numbers and letters print 
correctly as expected.

Thank you 


#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv)
            // Declare pointers
                int* ptr_one; // This points to an int
                char* ptr_two; // This points to a string

        // allocate space for 5 integers and assign to pointer 1
                ptr_one = (int *)malloc(sizeof(int)*5); 

        // allocate space for 10 characters and assign to pointer 2
                ptr_two = (char *)malloc(sizeof(char)*10); 
        //check for correct space allocation
                if (ptr_one == 0 || ptr_two == 0)
                        printf("ERROR: memory allocation problem\n");
                        return 1;

        // this goes into the first slot for the 5 integers. Each slot is 4 
bytes wide
                *ptr_one = 78; 
                *(ptr_one + 4) = 94;// this goes into the second slot 
                *(ptr_one + 8) = 22;// this goes into the third slot 
                *(ptr_one + 12) = 56;// this goes into the fourth slot 
        // this goes into the first slot for the 10 characters. Each slot is 
4 bytes wide
                *ptr_two = 'A';
                *(ptr_two + 4) = 'B';// this goes into the second slot 
                *(ptr_two + 8) = 'C';// this goes into the third slot 
                *(ptr_two + 12) = 'D';// this goes into the fourth slot 
                printf("%p contains %p\n", &ptr_one, ptr_one);// prints the 
address for ptr_one[0]
                printf("%p contains %d\n", &ptr_one[0], *ptr_one);// prints 78
                printf("%p contains %d\n", &ptr_one[1], *(ptr_one+4));// 
prints 94
                printf("%p contains %d\n", &ptr_one[2], *(ptr_one+8));// 
prints 67
                printf("%p contains %d\n", &ptr_one[3], *(ptr_one+12));// 
prints 56
                printf("%p contains %p\n", &ptr_two, ptr_two); // prints the 
address for ptr_two[0]
                printf("%p contains %c\n", &ptr_two[0], *ptr_two);// prints A
                printf("%p contains %c\n", &ptr_two[1], *(ptr_two+4));// 
prints B
                printf("%p contains %c\n", &ptr_two[2], *(ptr_two+8));// 
prints C
                printf("%p contains %c\n", &ptr_two[3], *(ptr_two+12));// 
prints D

        // Free the memory

    return (EXIT_SUCCESS);

Pointer Arithmetic Problem

ali_uk 02/01/2013

Re: Pointer Arithmetic Problem

Paul Floyd 02/01/2013

Pointer Arithmetic Problem

ali_uk 02/02/2013

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